Answers to Practice Exercises 1.4
Mathematical
Reasoning 2 :
Set
1 :
General Explanation
1.
The
number of runs scored by the players can be 2,3,5,7,11,13,17 and 19 not in any
order.
2.
Since
the difference between the number of runs scored by any 2 of the players is at
least 2, therefore both 2 and 3 together cannot be the scores of any 2 people.
3.
There
were 2 players who scored in single digits and P was one of them.
4.
Since
R scored 2 runs more than S, the scores of R and S must be either 11 and 13 or
17 and 19. Also, there is at least 1 player who has scored more than R.
Therefore, R cannot score 19 runs ie R must have scored 13 and S must have
scored 11 runs.
5.
Also
one player from Q or T must have scored either 17 or 19 runs while the other
must have scored in single digits.
6.
There
was exactly 2 pairs where the difference between the runs scored was exactly 8.
7.
If
the highest score is 17, then 17 cannot form such a pair. Therefore, the only
possibility is for 13 to form the pair with 5 and 11 to form the pair with 3.
The runs scored being 3,5,11,13 and 17.
8.
If
the highest score is 19, then one pair is already formed with 19 and 11. The
other pair can be 11 and 3 or 13 and 5 ie exactly one of the 2 numbers 3 or 5
can be scored in this case. This would mean that 7 is definitely one of the
runs scored.
Runs scored will be either 3 or 5 , 7 ,
11 , 13 and 19.
Ans 1 : Option d
Either 17 or 19 runs.
Ans 2 : Option c
Ans 3 : Option b
Ans 4 : Option d
Ans 5 : Option b
Set
2 :
General
Explanation:
1.
The
Ratio of the total number of boys and girls in PKG. is 3:5 . Let it be 3x and
5x respectively. The number of Boys is 48 less than the number of Girls.
ie 2x=48 or x=24 ie there will be a
total of 72 Boys and 120 Girls.
2.
The
Ratio of the number of Boys in the 3 section is 1:1:2 ie the number of Boys
will be 24,24 and 48 respectively.
3.
There
were 30 Girls in Section B which means that there were 90 Girls in A and C
together with Sections A having 10 girls more than Section B.
The Distribution of Boys and Girls is
as follows:
Ans
6 : Option b
Ans
7 : Option c
Ans
8 : Option a
Ans
9 : Option a
Ans
10 : Option c
Set
3 :
Ans 11 : Option a
The Punter has placed Rs.100 on each of
the Events happening ie he has placed a Bet of Rs.300/-. If he wants the
maximum return, he would want each of the events to happen. Therefore, total
Returns will be = 200+150+100= 450
Return = (450-300/300)*100 = 50%.
Ans 12 : Option b
Exactly 2 Events Event A and Event C
must have happened.
Ans 13 : Option b
Ans 14 : Option a
Minimum Percentage return will be when
none of the events have happened.
The total money that he will get back
is Rs.50/-
Percentage Return = (50/300)*100 = 16.66 %
Set
4 :
General Explanation:
1.
There
is only 1 Bag which contains equal number of Balls of each type. This must be
Bag B having 10 Balls of each type.
2.
The
Number of Yellow balls in B and C must be the same. Since Bag B has 10 Yellow
balls, Bag C must also have 10 Yellow balls. Therefore, the Number of Green
balls in Bag C must be 8.
3.
The
Number of Green Balls in Bag A must also be 8. The Number of Yellow balls in
Bag A must be 17.
|
A
|
B
|
C
|
Red Balls
|
5
|
10
|
12
|
Green Balls
|
8
|
10
|
8
|
Yellow Balls
|
17
|
10
|
10
|
Total weight (in gms.)
|
510
|
450
|
440
|
|
|
|
|
Ans
15 : Option a
Ans
16 : Option b
=(14/11)*100
Ans
17 : Option a
Ans
18 : Option c
Ans
19 : Option b
Ans
20 : Option c
Miscellaneous
1 :
Set
1 :
General Explanation :
1.
Let
Mehu’s 1st Statement be true. Therefore, Mehu was the First one to
finish. Also, her 2nd statement must be false ie Dan Bhai must have
been given Milk.
2.
Reyu’s
2nd Statement is therefore True and so his 1st Statement
must be False ie Reyu was not given Boost. Therefore, Reyu must have been given
Juice.
3.
Dan
Bhai’s 2nd Statement is False and therefore the 1st
Statement must be true. If Dan Bhai is not the last to finish, Dan Bhai must
have finished 2nd and Reyu must have finished last.
Mehu : First : Boost
Dan Bhai : Second : Milk
Reyu : Third : Juice
4.
Let
Mehu’s 2nd Statement be true. ie Dan Bhai was not given Milk. Also
her first Statement is False ie Mehu actually did not finish First.
5.
Reyu’s
2nd Statement is False and so his First Statement must be True ie
Reyu was given Boost to drink.
6.
Dan
Bhai’s 2nd Statement is False and so his First Statement is True ie
Dan Bhai did not finish last.
Possibilities are :
First : Reyu : Boost
Second : Dan Bhai : Juice
Third : Mehu : Milk
Or
First : Dan Bhai : Juice
Second : Mehu : Milk
Third : Reyu : Boost
Or
First : Dan Bhai : Juice
Second : Reyu : Boost
Third : Mehu :
Milk
Ans 1 : Option c
Ans 2 : Option d
Ans 3 : Option a
Ans 4 : Option d
Set 2 : This set can be done
by simple observation
Ans 5 : Option a
Ans 6 : Option b
Ans 7 : Option c
All the other pairs have dissimilarity
level of 4.
Ans 8 : Option a
Set
3 :
General
Explanation :
1.
If
n is the number of cuts in each direction, in this case, all the answers can be
generalized.
2.
The
number of Cubes with 3 sides painted will be on the Corners of the Main Cube.
Since a Cube has 8 Corners, the number of Cubes with 3 faces painted will be =
8.
3.
The
number of Cubes with 2 faces painted will be along the edge of the Main Cube
and there will be (n-2) such Cubes along each edge.
Number of such Cubes = (n-2)*12
4.
The
number of Cubes with 1 face painted will be on the Faces of the Main Cube and
there will be (n-2)^2 Cubes on each Face.
Number of such Cubes = 6x(n-2)^2.
5.
The
Number of Cubes with no face painted will be = (n-2)^3
Ans 9 : Option d
There will be a total of 6*(n-2)^2 Cubes = 6*(4-2)^2 = 24
Ans 10 : Option b
Ans 11 : Option c
Ans 12 : Option d
Set
4 :
Ans
13 : Option d
Ans
14 : Option a
Ans
15 : Option c
Ans
16 : Option a
Set
5 :
General
Explanation:
1.
Let
the statement of Z be true. Therefore exactly one of V or Y is true and one is
false. Also, W’s statement is False.
2.
Since
3 people gave false Statements, therefore Y has definitely given a False
statement.
3.
Out
of the other 3 people, U,V and X exactly 2 people gave True Statements.
2nd Case :
1.
Let
the Statement of Z be False ie either both V and Y gave true statements or both
gave false statements. But since Y has definitely given a false statement,
therefore, V must also have given a false statement.
2.
All
the other 3 people U,X and W must have given true Statements.
Ans 17 : Option c
Ans 18 : Option d
Either Son or Daughter
Ans 19 : Option b
Ans 20 : Option a
Miscellaneous
2 :
Set
1:
General
Explanations :
1.
If
we look at the total cost of all the items put together, it is Rs.44 ie the
average amount spent by all the 4 people together is Rs.11 which is not the
price of any of the items. Therefore, Omita’s first statement is False and
therefore the second statement will be true, ie Pradeep did not have a Dhokla.
2.
From
the above point, Neetu’s second statement is False and so the first statement
will be true.
3.
Omita
had the costliest item and therefore, Madan’s second statement will be False
and the first will be True. Madan had a Dhokla which was priced at 12/-.
4.
If
Pradeep’s second statement is False, then it would mean that a Samosa is priced
at Rs.14 and so Omita must have had a Samosa. This also means Pradeep’s first
statement is true which says that Omita had a Kachori which in turn contradicts
the first part.
5.
Therefore,
Pradeep’s first statement is False ie Omita must have had either a Samosa or Rasmalai.
The second statement is true ie a Samosa is not priced at Rs.14/-and so Omita
must have had a Rasmalai.
6.
Madan
: Dhokla : Rs.12/-
Omita : Rasmalai : Rs.14/-
Neetu : Dhokla : Rs.8 or 10/-
Pradeep : Kachori : Rs.8 or 10/-
Ans 1 : Option c
Ans 2 : Option b
Ans 3 : Option a
Ans 4 : Option c
Ans 5 : Option d
Set
2 :
General Explanation :
1.
Let
us try to arrange them in order of Fairness and Height.
2.
Fairness
: B<A, C<D, E<B, A<F, C<E, D<E
Compiling the data together, we get
C<D<E<B<A<F
3.
Height
: A<F, A<C, F<B, C<F, E<C, D<E
Compiling the data together, we get
D<E<C<F<B and A<C
Ans 6 : Option d
Ans 7 : Option b
Ans 8 : Option b
Ans 9 : Option c
Ans 10 : Option c
Set
3 :
Ans 11 : Option a
Ans 12 : Option b
Ans 13 : Option c
Ans 14 : Option d
Ans 15 : Option d. There will be 90 such cubes which will
not have Red colour on any of it’s faces.
Set
4 :
Ans 16 : Option b
By counting we can observe that the 4
candidates who had taken a Group A subject in Prelims cannot choose Sociology a
Group A subject in the Mains.
Ans 17 : Option a
Since E has choosen Hindi in Prelims,
he or she cannot choose a Group A subject in Mains. Further, Sanskrit has to be
definitely choosen. The second subject can be any one out of Geography,
Physics, History and Pub.Ad. The 2nd subject cannot be Physics,
since Geography has to be definitely choosen with Physics. Also, History and
Sanskrit cannot be choosen together for Mains.
The 2nd Subject for Mains
can be either Geography or Pub.Ad.
Ans 18 : Option d
If a person has choosen Geography as
one of the subjects in Mains, the 2nd subject can be any one of the
other 8 subjects except Hindi.
Ans 19 : Option b
Ans 20 : Option c
Required number of ways will be = 10C2.
Coding
Decoding, Series Completion, Direction Sense 1 :
Ans 1 : Option b
Coding is in the Reverse order
alphabet+1, alphabet+2 and so on
Ans 2 : Option c
Ans 3 : Option a
Ans 4 : Option d
Difference between consecutive terms of
17,24,31 and so on
Ans 5 : Option a
x4+4, x6+6, x8+8 and so on
Ans 6 : Option b
Differences of squares of numbers ie
differences of 1,4,9,16 and so on.
Ans 7 : Option c
Ans 8 : Option c
General
Explanation for Qs 9 to 11 :
The machine is doing the arrangement
based on the last alphabet in the word and the entire arrangement is being done
from Z to A.
Ans 9 : Option b
Ans 10 : Option d
It would be the 5th step.
Ans 11 : Option d
Ans 12 : Option c
Ans 13 : Option b
Ans 14 : Option a
Immediate next alphabet but coding is
one from beginning followed by one from end.
Ans 15 : Option b
Ans 16 : Option c
(Squares of odd numbers)-1
Ans 17 : Option d
Ans 18 : Option d
The answer is cannot be determined
because it will depend on whether Seema is to the right or left of Rekha.
Ans 19 : Option c
Ans 20 : Option c
Coding
Decoding, Series Completion, Direction Sense 2 :
Set
1 :
General
Explanation:
1.
Compare
the first 2 words, 1,4,3 represents e,l,p in no particular order. Therefore a=2
and O=7.
2.
Compare
words 1 and 3. L=1
3.
Compare
words 3 and 4, y=5
4.
e=3,
r=8, p=4, z=6
Ans 1 : Option c
Ans 2 : Option a
Ans 3 : Option a
All the terms are products of
consecutive prime numbers.
Ans 4 : Option c
The Series is 1^1, 2^2, 3^3, 4^4 and so on.
Ans 5 : Option d
The series is (Each term x 2) + or – 1
alternately.
Ans 6 : Option b
Ans 7 : Option b
General
Explanation for Questions 8 to 11 :
1.
The
Machine arranges each item based on the sum of it’s digits from left to right.
Ans 8 : Option c
Ans 9 : Option c
Ans 10 : Option d
Ans 11 : Option c
Ans 12 : Option b
The Series is (x1+1), (x2+2), (x3+3)
Ans 13 : Option d
The Series is made using the product of
the digits.
Ans 14 : Option c
(Squares of Numbers-1) and (Squares of
Numbers+1)
Ans 15 : Option a
Ans 16 : Option d
Ans 17 : Option b
Ans 18 : Option c
Ans 19 : Option c
Two alphabets are used for each code,
one the immediately preceeding alphabet and the other the immediate following
one.
Ans 20 : Option b
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